A jogger travels a route that has two parts. The first is a displacement A right

Question

A jogger travels a route that has two parts. The first is a displacement A rightarrow of 2.50 km due south, and the second involves a displacement B rightarrow that points due east. The resultant displacement A rightarrow + B rightarrow has a magnitude of 4.29 km. What is the magnitude of B rightarrow? What is the direction of A rightarrow + B rightarrow relative to due south? Suppose that A rightarrow - B rightarrow had a magnitude of 4.29 km. What then would be the magnitude of B rightarrow and what is the direction of A rightarrow - B rightarrow relative to due south? magnitude of B rightarrow direction of A rightarrow - B rightarrow relative to due south

Explanation / Answer

a) mag = sqrt(x^2 + y^2)

4.29 = sqrt(x^2 + 2.5^2)

x=3.49 km

direction = arctan(3.49/2.5)=54.38 degrees east

b) same mag 3.49 km

now 54.38 degrees west

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