1. Compare the resistance for copper wires of the SAME radius but DIFFERENT leng
ID: 2269318 • Letter: 1
Question
1. Compare the resistance for copper wires of the SAME radius but DIFFERENT lengths. CALCULATE the ratio of lengths and compare to the ratio of resistances.Compare the resistances for copper wires the SAME length but DIFFERENT radii. CALCULATE the ratio of cross-sectional areas and compare to the ratio of resistances.Are the above results consistent with the theoretical relationship between resistance and resistivity? Were your predictions for the order of coil resistances correct? If not, try to understand why. You must answer all parts of the question in order to receive full credit.Part C: Resistivity WRITE UNITS DOWN Record Coil Characteristics: CoilMaterial Area, A Length, L meters Diameter,Inches Radius, R,metersCrOss 804 1o Calculations for Area: 2 (3.00 Coil&Voltage; %Dif. Handbook Material | across coil | Through coil | Resistance, I ResistivityPoi | Resistivity, Pm cu 0,169 0 55110 172 x10295 2cu lo.sew | i.0L | aws a | 77%× 11,72 tiat rem-. ,4 .ia) 5.5.*s* . . . PartDi Effectof Heatingon Resistivinand Resistance, Coil #/ Current (A) Vcal Resistance V ,,toes Resistance | % change | Heating Resistance) ) Material__ (constant) t-0)-(t-o) 2min.)02 min.) Cu Cu #3 Cu #4 Cu 20 1.00 A 1.00A 3.73 v 20 c
Explanation / Answer
1.
resistance is R = rho*l/A
rho is the resistivity of copper
l is the length of the wire
A is the area of cross section = pi*r^2
r is the radius of the wire
for the same copper material rho is same
and given that same radius,thus A is also same
R = rho*l/A
i.e more is the length of the wire then more is the resistance of the wire
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if length is same
R is inversely proportional to the square of the radius of the wire
more is the radius of the wire then smaller is the Resistance of teh wire
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