3.) 1.) Opening the switch: a.) Enables current in RLoad because the resulting g
ID: 2266762 • Letter: 3
Question
3.)
1.) Opening the switch:
a.) Enables current in RLoad because the resulting gate voltage turns the MOSFET on
b.) Disables current in RLoad because there is no switch current
c.) Disables current in RLoad because all of the current flows through the gate to ground
d.) Enables current in RLoad because the load current flows through the shorted switch
2.) Compute VD when the MOSFET is on
a.) 0.500 V
b.) 0.600 V
c.) 0.120 V
d.) 0.165 V
a.) 2.65 V
b.) 12.6 V
c.) 9.86 V
d.) 3.16 V
4.) Compute the power dissipation in the MOSFET when it is on
a.) 0.720 W
b.) 0.450 W
c.) 0.338 W
d.) 0.372 W
5.) When the MOSFET is off
a.) Power dissipation in RG exceeds power dissipation in RLoad
b.) VG < Vt
c.) Neither a or b
d.) Both a and b
Explanation / Answer
Answer:-1) Option a is correct. When switch is open then gate voltage is not equal to zero(more than zero). So non-zero gate voltage makes MOSFET in ON state because it is a n-channel MOSFET, and hence current flows through load. Note MOSFET is a voltage controlled device i.e voltage applied on the gate terminal will control the current flowing in the channel.
Answer:-2) Option d is correct. Given that when mosfet is ON then drain current ID = 2.05 mA. So by applying KVL we can write-
18 - (8.7 x 2.05 ) - VD = 0
=> VD = 0.165 V.
Answer:-5) Option d is correct.
When MOSFET is OFF i.e the switch is closed hence gate voltage is zero, so VG < Vt.
When MOSFET is OFF then no load current flows but current through RG is maximum. Hence power dissipation in RG exceeds power in RLOAD.
Dear student kindly once check the values provided in the question, since when I solve rest two the answers are comming but in mili and not matching with option. Just try to check for value of ID. Thanks.
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