The graph is the force exerted by a spring as a function of thedistance it is st

Question

The graph is the force exerted by a spring as a function of thedistance it is stretched from its unstretched length. What isthe spring constant of this spring? What is the elasticpotential energy if the spring is stretched 1.5 m from itsequilibrium length? A low friction cart of mass 5.0 kg isattached to the spring, the spring is stretched1.5 m from itsequilibrium length, and then the cart is released. What isthe kinetic energy of the cart just as the spring passes throughits equilibrium length? What is the velocity of the cart?

Explanation / Answer

(a) By F = - kx
=>k = F/x = 12/5 = 2.4 N/m [ignore the -ve sign as it indicates the direction of the force]
(b) By PE(spring) = 1/2kx^2 = 1/2 x 2.4 x (1.5)^2 = 2.7 J
(c) By PE(spring) = KE(cart) at the spring passes through its equilibrium position
=>KE(cart) = 2.7 J
=>By KE = 1/2mv^2
=>2.7 = 1/2 x 0.5 x v^2
=>v = sqrt[10.8] = 3.29 m/s

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.