Just the wheel. Just Dylan. The wheel and Dylan. The wheel, Dylan, and the bar s
ID: 2264499 • Letter: J
Question
Just the wheel.Just Dylan. The wheel and Dylan.The wheel, Dylan, and the bar stool. up (counterclockwise)down (clockwise) Dylan sits on a bar stool, with his feet off of the floor. The seat of the bar stool is free to rotate. Dylan is holding a wheel (moment of inertia = 1.84 kg m2) that is spinning counterclockwise at an angular speed of 16.40 rad/s, as shown below, and Dylan and the bar stool are not rotating. (Dylan + the bar stool have a moment of inertia of 58.60 kg m2.) Dylan, being curious, presses his hand against the edge of the wheel (applying an internal torque), and the angular speed of the wheel slows to 1.66 rad/s. What happens to Dylan? What is "the system" for this problem? Just the wheel. Just Dylan. The wheel and Dylan. The wheel, Dylan, and the bar stool. What is the magnitude of the total angular momentum of the system? What is the magnitude of Dylan's angular velocity when the wheel is spinning at 1.66 rad/s? What direction is Dylan's angular velocity when the wheel is spinning at 1.66 rad/s? (One Submission) up (counterclockwise) down (clockwise)Explanation / Answer
for wheel
Ia=1.84 kg/m2
wi=16.4 rad/s
wf=1.66rad/s
for dylan+stool,
Ib=58.6 kg/m2
w=??
a) system= wheel+dylan+barstool
b)L=Ia x wi = 1.84*16.4=30.17
c) since, no extwrnal torque is acting on system,total angular momentum must be constant
hence,
( Ia x wi) = ( Ia x wf) + (Ib x w)
30.17=1.84*1.66 + 58.6*w
w=0.462
d) down(clockwise) , since angular momentum need to be conserved.
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