machinist is using a wrench to loosen a nut. The wrench is L = 24.5 cm long, and

Question

machinist is using a wrench to loosen a nut. The wrench is L = 24.5 cm long, and he exerts a F = 21.5-N force at the end of the handle at ? = 36.0

machinist is using a wrench to loosen a nut. The wrench is L = 24.5 cm long, and he exerts a F = 21.5-N force at the end of the handle at ? = 36.0 degree with the handle (see figure below). What torque does the machinist exert about the center of the nut? What is the maximum torque (magnitude) he could exert with this force? How should the force be oriented? ? = 90 degree (perpendicular to the wrench) ? = 0 degree (parallel to the wrench) ? = 45Degree

Explanation / Answer

(a) Magnitude = F*l sin theta = 21.5*0.245 sin36 = 3.096 N.m

Direction is counter clockwise

(b) max is when sin theta is maximum.

theta = 90 degrees

Magnitude of max = 21.5*0.245 * 1 = 5.2675 N.m

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