For the situation described above, what is the work done on the particle by the

Question

For the situation described above, what is the work done on the particle by the force from x = -5.00 m to  x = 12.00 m.

Im sure the work is the area under the curve but I keep getting the wrong answer, please help

Shown below is a graph of the 1-dimensional, net force as a function of position, F(x), that you exert on a particle of mass 5 kg. Note 1: It may be easier to solve these problems in a different order than they are asked. Note 2: F = 0 at x = 10.286 m. The particle starts at x = -5 m with a velocity of 8.480 m/s and reaches x = 12.00 m under the action of the force in the graph. What is the impulse that you give to the particle as it moves from x = -5.00 m until it reaches x = 12.00 m. Remember that impulse is a vector, so in 1-dimension it can be either positive or negative.

Explanation / Answer

b) total work done = area under the curve.


W = 5*6 - 0.5*6*10.286 + 0.5*1*(12-10.286)

W = 0.001 J

a) to find impulse m
ass of the particle should be gicen

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