Question
Attached:
Forces in a Three-Charge System Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is |F| = K |QQ'|/d2 where K = and = = 8.854x10-12 C2/(N m2) is the permittivity of free space. Consider two point charges located on the x axis: one charge, q1 = -17.5 nC, is located at x1 = -1.650m; the second charge, q2 = 37.0nC, is at the origin (x = 0.0000). W hat is the net force exerted by these two charges on a third charge q3 = 49.0nC placed between q1 and q2 at x3 = -1.085m ? Your answer may be positive or negative, depending on the direction of the force Express your answer numerically in newtons to three significant figures.
Explanation / Answer
F = -k q1 q3/r13^2 - k q2 q3/(r23)^2 = -9e9*17.5e-9*49e-9/(1.65-1.085)y2 - 9e9*37e-9*49e-9/(1.085)y2 ===============> F = -3.80 x 10^-5 N
