Answer v R = v 0 + v F ln(m R /m 0 ) v R = v 0 - v F ln(m R /m 0 ) v R = v 0 - v

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Answer            

       

                            
           vR = v0 + vF ln(mR/m0)                             
           vR = v0 - vF ln(mR/m0)                             
           vR = v0 - vF exp(m0/mR)                             
           vR = v0 - vF ln(m0/mR )                             
           vR = v0 + vF exp(mR/m0) A rocket is moving in outer space where no external forces exist. Suppose its mass is mR and its velocity is vR at a particular time. When a mass mF of fuel is ejected, the mass of the rocket becomes (mR - mF) and its velocity increases to (vR+ vR). Suppose the fuel is always ejected at a constant speed vF with respect to the rocket. Derive an expression for vR as a function of mR given the rocket's initial mass and speed are m0 and v0, respectively

Explanation / Answer

vR = v0 - vF ln(mR/m0)

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