a)-The massive grinder for wood-pulp in a newsprint paper factory, which can ren
ID: 2260985 • Letter: A
Question
Explanation / Answer
Answer:
moment of inertia = 1/2*mR^2
omega = 2pi*frequency
rotational energy = 1/2*I*?^2
E rot = 1/2*(1/2*6000*0.65^2)(2pi*66/60)^2
E rot = 30273.53 Nm <-- ans.
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The grinding wheel comes to rest in 60 ms (milliseconds)
First find the angular acceleration, using the standard constant acceleration equations but with s v and a.
wf= wi+ at
wf= 0, so
-wi= at
(where wi= 66 rpm/60 sec * 2pi rad = 6.91 rad/s)
so
- 6.91 = a(.06)
a= -115.19 rad/s2
so the tangential force is
thnq
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