SHOW WORK A free neutron is unstable and will decay with a half-life of 10 minut
ID: 2260843 • Letter: S
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SHOW WORK
A free neutron is unstable and will decay with a half-life of 10 minutes to a proton, an electron and an anti-neutrino. (The existence of the latter was discovered because scientists refused to believe that conservation of momentum could ever by violated!) Given that the mass of a neutron is mn = 1.674 times10-27 kg, of a proton is mp = 1.673 times 10-27 kg, and the mass of an electron is 9.1 times 10-31 kg, if a neutron at rest decays to a proton traveling 300 m/s East, an electron traveling 30000 m/s along a line 45 degree West of North, what is the momentum of the anti-neutrino? /5 4.8 times lO-25 kgm/s 4.8 times 10-25 kg m/s x^ + 1.93 times 10-26 kgm/s y^ 1.93 times 10-26 kg m/s - 4.8 times 10-25 kg m/s 1.93 times 10-26 kg m/s y^ 5.02 times 10-25 kg m/s x^Explanation / Answer
momentum is coserved so
initial momentum = final momentum = 0
1. in east direction 673*300*10^(-27) - 9.1*30000*cos(45)*10^(-31) = 4.82 *10^(-25) i
in north direction = 9.1*30000*sin(45)*10^(-31)= 1.93*10^(-26) j
b answer
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