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SHOW CALCULATIONS FOR THE FOLLOWING 1.) How many moles is 48.2g of Si? b. How ma

ID: 1006223 • Letter: S

Question

SHOW CALCULATIONS FOR THE FOLLOWING

1.) How many moles is 48.2g of Si?

b. How many atoms

2.) A compund of carbon and hydrogen and oxygen ( ethylene glycole-antifreeze) is determined to be 38.7% C , 51.6% O, and 9.7%H . Calculate the molecular formula if the molar mass is 62.1g/mol. Show calculations.

3.)How many grams of Fe can be recovered from 35.0g of Fe2O3? Show calculations

4.) How many atoms of O in 4.80g of Ca(ClO3)2? Show calculations.

5.)How many liters(at STP) are 5.39 * 10^25 molecules of nitrogen monoxide?

6.) Describe the preparation of 500. ml of a .150M LiNO3 solution. Show calculation.

7.)a. Write a complete balanced conventional (Molecular ) equation . b.) Wite the complete ionic equation. c). Write the net ionic equation and include all the charges for the following.

i.) A solution of Barium nitrate is added to a solution of sodium hydroxide.

ii) A solution of ammonium hydroxide is mixed with a solution of aluminum nitrate.

iii)A solution of strontium hydroxide is added to a solution of hydrochloric acid.

iv) A solution of copper(II) chloride is mixed with a solution of sodium carbonate.

Explanation / Answer

1. no of moles of Si = W/G.A.Wt

                                  = 48.2/28 = 1.72 moles

no of atoms = no of moles * 6.023*1023

                              = 1.72 *6.023*1023

                      = 1.036*1024 atoms

2.

Element                %              At.Wt     Relative number          simple ratio

C                       38.7              12                                   38.7/12 = 3.225                                       3.225/3.225 = 1

H                     9.7                  1                                     9.7/1   = 9.7                                                 9.7/3.225     = 3

O                   51.6               16                                      51.6/16 = 3.225                                        3.225/3.225 = 1

     Empirical formula = CH3O   = 31

empirical formula mass = 12+3+16

molecular formula   = (empirical formula)n

                    n          = molar mass/empirical formula mass

                                = 62.1/31   = 2

molecular formula    = (CH3O)2

                                    C2H6O2 >>>> answer

3.)How many grams of Fe can be recovered from 35.0g of Fe2O3?

no of moles of Fe2O3 = 35/160 = 0.218 moles

Fe2o3-     ------> 2Fe

0.218 moles       2*0.218 = 0.436 moles

mass of Fe = no of moles * atomic mass of Fe

                    = 0.436*56 = 24.416g