This is a question from my physics lab however we havent talked about this in le

Question

This is a question from my physics lab however we havent talked about this in lecture yet and i have no idea where to start.  Please show steps I need to understand.

Three equal charges of amount Q are placed at the vertices of a square of side a as illustrated at the right. Determine: the total electric field (both magnitude and direction) produced by the three charges at point A. Make sure to draw electric field vectors and its components on the figure the total electric potential produced by the three charges at point A the Coulumb force at point A(both magnitude and direction) if there is a charge -Q placed at given the value Q = 9.50nC , a is 6.00cm, find numerical values of electric field and force.

Explanation / Answer

a)

Ex = -k(2Q)/a^2 - kQ/2a^2 = -kQ/a^2 (2 + 1/2) = -2.5 k Q/a^2

Ey = k(Q)/a^2 - kQ/2a^2 = kQ/a^2 (1 - 1/2) = 0.5 k Q/a^2

E = sqrt(Ex^2 + Ey^2) = sqrt((-2.5 k Q/a^2)^2 + (0.5 k Q/a^2)^2) = 6.5 k Q/a^2

direction: 180 - arctan(0.5/2.5) = 169 degrees

b)

V = k (2Q)/a - k Q/a + k Q/(sqrt(2) a) = (kQ/a) (2 - 1 + 1/sqrt(2)) = 1.707 k Q/a

c)

magnitude:

F = Q E = 6.5 k Q^2/a^2

direction:

180 + 169 = 349 degrees

e)

E = 6.5 k Q/a^2 = 6.5*9e9*9.5e-9/(0.06*0.06) = 1.54 x 10^5 N/C

F = 6.5 k Q^2/a^2 = 6.5*9e9*9.5e-9**9.5e-9/(0.06*0.06) = 1.47 x 10^-3 N/C

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