1) 2) 3) 4) What is the direction of I 3 ? ........multi choice.....]] A rectang
ID: 2260239 • Letter: 1
Question
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What is the direction of I3? ........multi choice.....]]
A rectangular loop of wire with sides H = 31 cm and W = 51 cm carries current I2 = 0.389 A. An infinite straight wire, located a distance L = 25 cm from segment ad of the loop as shown, carries current I1 = 0.602 A in the positive y-direction. What is Fad,x, the x-component of the force exerted by the infinite wire on segment ad of the loop? N What is Fbc,x, the x-component of the force exerted by the infinite wire on segment bc of the loop?. N What is Fnet,y, the y-component of the net force exerted by the infinite wire on the loop? N Another infinite straight wire, aligned with the y-axis is now added at a distance 2L = 50 cm from segment bc of the loop as shown. A current, I3, flows in this wire. The loop now experiences a net force of zero. What is the direction of I3? ........multi choice.....]] along the positive y-direction along the negative y-direction: What is the magnitude of I3?Explanation / Answer
H = 0.31 m
W = 0.51 m
L = 0.25m
i1 = 0.602 A
i2 = 0.389 A
1) Fad = mue*i1*i2*H/(2*pi*L) = 5.8*10^-8 N(towards +x axis)
2) Fbc = mue*i1*i2*H/(2*pi*(L+W)) = 1.91*10^-8 N(towards - x axis)
Force on loop due to i1, F1 = Fad - Fbc = 3.89*10^-8 N(towards +x axis)
3) Fnet,y = 0( because on upper and lower sections magnetic force acts in the opposite direction)
4) along the negative y direction
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1) Fad = mue*i3*i2*H/(2*pi*(2L+W)) = i3*2.388*10^-8 N(towards +x axis)
2) Fbc = mue*i3*i2*H/(2*pi*2L) = i3*4.8236*10^-8 N(towards - x axis)
Force on loop due to i3, F3 = Fad - Fbc = -i3*2.4356*10^-8 N(towards -x axis)
when net force is zero
F1 = F2
3.89*10^-8 = i3*2.4356*10^-8
i3 = 3.89*10^-8/(2.4356*10^-8) = 1.6 A
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