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1) 2) 3) 4) What is the direction of I 3 ? ........multi choice.....]] A rectang

ID: 2260239 • Letter: 1

Question

                                1)                             

                                2)                             

                                3)                             

                                4)                             

                                What is the direction of I3? ........multi choice.....]]                             

A rectangular loop of wire with sides H = 31 cm and W = 51 cm carries current I2 = 0.389 A. An infinite straight wire, located a distance L = 25 cm from segment ad of the loop as shown, carries current I1 = 0.602 A in the positive y-direction. What is Fad,x, the x-component of the force exerted by the infinite wire on segment ad of the loop? N What is Fbc,x, the x-component of the force exerted by the infinite wire on segment bc of the loop?. N What is Fnet,y, the y-component of the net force exerted by the infinite wire on the loop? N Another infinite straight wire, aligned with the y-axis is now added at a distance 2L = 50 cm from segment bc of the loop as shown. A current, I3, flows in this wire. The loop now experiences a net force of zero. What is the direction of I3? ........multi choice.....]] along the positive y-direction along the negative y-direction: What is the magnitude of I3?

Explanation / Answer

H = 0.31 m
W = 0.51 m
L = 0.25m
i1 = 0.602 A
i2 = 0.389 A

1) Fad = mue*i1*i2*H/(2*pi*L) = 5.8*10^-8 N(towards +x axis)

2) Fbc = mue*i1*i2*H/(2*pi*(L+W)) = 1.91*10^-8 N(towards - x axis)

Force on loop due to i1, F1 = Fad - Fbc = 3.89*10^-8 N(towards +x axis)

3) Fnet,y = 0( because on upper and lower sections magnetic force acts in the opposite direction)

4) along the negative y direction


5)

1) Fad = mue*i3*i2*H/(2*pi*(2L+W)) = i3*2.388*10^-8 N(towards +x axis)

2) Fbc = mue*i3*i2*H/(2*pi*2L) = i3*4.8236*10^-8 N(towards - x axis)

Force on loop due to i3, F3 = Fad - Fbc = -i3*2.4356*10^-8 N(towards -x axis)


when net force is zero

F1 = F2

3.89*10^-8 = i3*2.4356*10^-8

i3 = 3.89*10^-8/(2.4356*10^-8) = 1.6 A