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please help. only right answers Thanks alot. a circular tube of polythelene plas

ID: 2260097 • Letter: P

Question

please help.

only right answers

Thanks alot.

a circular tube of polythelene plastic (p=930 kg/m^3) has an inside radius of 1.2 cm and an outside radius of 4.6. if the cylinder is 40cm long. what is the weight of the cylinder? an underground pipe carries water to a home at a volume flow rate of 5 gal/min. determine the flow rate in m^3/s and ft^3/h. a battery-operated radio requires a current of 200mA at 12V. find the energy consumed in 2 hours of operation. frictionless piston-cylinder device has a diameter of 10cm. as the gas inside the cylinder is heated, the piston moves a distance of 16 cm. if the gas pressure is maintained at 120 kPa, how much work is done? estimate the atmospheric pressure at an altitude of H=140 meters over sea level, knowing that the pressure at sea level is 1.013times10^5 Pascals. in your estimation assume the density of air to be constant P=1.29 kg/m^3. A pump draws 2kW electricity to pump water from a tank at rate of .05 m^3/s. what the maximum height that the water can be pumped to?

Explanation / Answer

1) Density,p=930 kg/m^3

Inner radius, r1= 1.2 cm

Outer radius,r2= 4.6cm

Length,l= 40cm

Volume of cylinder = pi(r2^2-r1^2)l

=3.14(4.6^2-1.2^2)x40

= 2476.82 cm^3

= 2476.82 x 10^-6 m ^3

Density= Mass/ Volume

Mass, m = density x volume

= 930 kg/m^3 x 2476.82 x 10^-6 m ^3

= 2.303 kg

  

thus, weight of cylinder= 2.303 kg


2) 1 gal= 0.0038 m^3=0.13368 ft^3

1 min = 60 sec

1 hr =60 min


flow rate= 5 gal/min

= 5 x 0.0038 / 60

=0.000216 m^3/s

flow rate= 5 gal/min

= 5 x 0.13368 x 60

= 40.104 ft^3/hr


3) current = 200mA =0.2 A

time = 2hrs = 2 x 60 x 60 sec

Energy consumed= Voltage x current x time

= 12 x 0.2 x 2 x 60 x 60

=17.28 kJ


4) Work Done = force x distance

= pressure x area x distance

= 241.152 N-m


5) Pressure= pressure at sea level - densityx acceleration due to gravity x altitude

=1.013 x 10^5 - 1.29x9.81x140

= 0.99528x 10^5 Pa

6) power = density of water x accleration due to gravity x discharge x height

2000 = 1000 x 9.81 x 0.05 x height

Height= 4.0774m