please help, cant be wrong here If 100 g of steam at 100 degree C were mixed wit

Question

please help, cant be wrong here

If 100 g of steam at 100 degree C were mixed with 10 kg of ice at -100 degree C, find the final temperature of the mixture assuming no heat losses to the surroundings. An ideal gas undergoes a cyclic process in which total (positive) work W is done by the gas. What total heat is added to the gas in one cycle? W -W zero 2W W/2 Fifteen identical particles have various speeds: one has a speed of 2.00 m/s; two have speeds of 3.00 m/s; three have speeds of 5.00 m/s; four have speeds of 7.00 m/s; three have speeds of 9.00 m/s; and two have speeds of 12.0 m/s. (a) Find the average speed, the rms speed, and the most probable speed.

Explanation / Answer

12) Let the final temperature be t.

Heat required to bring 10 kg ice to 10 kg ice at 0 C = Heat required to bring 100 kg ice from -100 C to 0 C

H = mass*specific heat of ice*temperature difference = 10000*0.5*100 = 500000 Cal

Heat required to bring 100 gm steam to 100 gm water at 100 C = Heat req to transform 100 gm ice to 100 gm water at 100 C

H = mass*latent heat of condensation = 100*540 = 54000

Heat required to bring 100 gm water from 100 C to 0 C = Mass*specific heat of water*temperature difference = 100*1*100 = 10000

So now when all of steam is converted to water heat released in the process = 10000+54000 = 64000

Since this amount is not enough to bring the Ice from -100 C to 0 C, the water will start transforming to ice.

Do amount of heat released when 100 gm water is tramsformed to ice = 100*80 = 800

So we now have 100 gm water a 0 C and total heat released = 64800 cal

This energy is gained by the ice at -100 C.

Increase in heat by the ice = 64800/10000*0.5 = 12.96

So now we have 10 kg ice at (-100+12.96) C = -87.04 C and 100 gm ice at 0 C

Let the final temperature be t

So 10000*0.5*(87.04-t) = 100*0.5*t

5000*87.04 = 5050t

t = 5000*87.04/5050 = 86.178 C

So the final temperature is -86.178 C

(1

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.