( I OUT / I IN )*100% = % [0.75 points] 0 attempt(s) made (maximum allowed for c

Question

(IOUT/IIN)*100% = %     
[0.75 points] 0 attempt(s) made (maximum allowed for credit = 5)

(IOUT/IIN)*100% = %     
[0.75 points] 0 attempt(s) made (maximum allowed for credit = 5)

Unpolarized light (Intensity IIN) passes through two polarizers. The axis of the first one is vertical and of the second is at 90degrees to the vertical. What percentage of the light is transmitted? Unpolarized light (Intensity IIN) passes through three polarizers. The axis of the first one is vertical and the second is at 90degrees to the vertical. The third polarizer is located between the first and the second polarizers. The axis of the third polarizer is at 45degrees from the vertical. What percentage of the light is transmitted?

Explanation / Answer

(a) .5*(cos(90))^2=0

(b) .5*(cos(45))^2=0.25

.25*(cos(90-45))^2=.125

.125x100=12.5%

I had the same question and these were the right answers for me so I hope this helps you out.

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.