( 5/2/2016 11:55 PM O 742/1005/2/2016 02:57 PM Print Calculator Periodic Table Q
ID: 992331 • Letter: #
Question
( 5/2/2016 11:55 PM O 742/1005/2/2016 02:57 PM Print Calculator Periodic Table Question 24 of Map University Science Books presented by Sapling Leaming Donald McQuarie Peter A Rock Ethan Gallogy Calculate [H3O+], [CIO,-], and [OH-] in an aqueous solution that is 0.105 M in HCIO4(aq) at 25 Number Incorrect. As a strong acid, HCIO4 ionizes completely HCIO4(aq) H (aq) + C104 (aq. One mole of HCIO4 produces one mole each of H and CIO4. Similarly, 0.105 mol/L of HCIO4 produces 0.105 moVL of each ion CIO, I= Number OH8x 10-1 ls the solution acidic, basic or neutral? O acidic O basic O neutral Previous Give Up & View Solution Try Again Next ExitExplanation / Answer
HClO4 --> H+ + OClO4-
[H+] = 0.105 M
then
[ClO-4] = [H+] due to stoichioiometry
that is
[ClO-4] = 0.105 M
finally
Kw = [H+][OH-]
10^-14 = (0.105 )([OH-])
[OH-] = (10^-14)/(0.105) = 9.5238*10^-14
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