Two ice pucks (one orange and one blue) of equal mass are involved in a perfectl

Question

Two ice pucks (one orange and one blue) of equal mass are involved in a perfectly elastic glancing collision as shown in the figure below. The orange puck is initially moving to the right at

Two ice pucks (one orange and one blue) of equal mass are involved in a perfectly elastic glancing collision as shown in the figure below. The orange puck is initially moving to the right at voi = 4.00 m/s, strikes the initially stationary blue puck, and moves off in a direction that makes an angle of ? = 34.0 degree with the horizontal axis while the blue puck makes an angle of = 56.0 degree with this axis as in figure (b). Note that for an elastic collision of two equal masses, the separation angle ? + phi= 90.0degree. Determine the speed of each puck after the collision.

Explanation / Answer

y direction

m vof sin(34) + m vbf sin(56) = 0

==> vof sin(34) + vbf sin(56) = 0

==> vbf = vof sin(34)/sin(56) = 0.67451 vof

x direction:

m voi = m vof cos(34) + m vbf cos(56)

==> voi = vof cos(34) + vbf cos(56)

==> 4 = vof * cos34 + (0.67451 vof) cos(56)

==> vof = 3.32 m/s

==> vbf = 0.67451 vof = 0.67451 * 3.32 = 2.24 m/s

------------------------------------------------------------------------

Answers:

vof = 3.32 m/s

vbf = 2.24 m/s

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.