The magnitude of the net force exerted in the x direction on a 2.80-kg particle
ID: 2259824 • Letter: T
Question
The magnitude of the net force exerted in the x direction on a 2.80-kg particle varies in time as shown in the figure below.
(a) Find the impulse of the force over the 5.00-s time interval.
(b) Find the final velocity the particle attains if it is originally at rest.
(d) Find the average force exerted on the particle for the time interval between 0 and 5.00 s.
The magnitude of the net force exerted in the x direction on a 2.80-kg particle varies in time as shown in the figure below. Find the impulse of the force over the 5.00-s time interval. Find the final velocity the particle attains if it is originally at rest. Find its final velocity if its original velocity is -2.70 i hat bold m/s. Find the average force exerted on the particle for the time interval between 0 and 5.00 s.Explanation / Answer
I found the area under the plot to be 12 square units.
I did this by dividing the area into two triangles of area 4 and one rectangle of area 4, for a total of 12.
This value is equal to the average force multiplied by the duration, which is the impulse.
(a) impulse = 12 Newton-seconds.
(d) The average force:
12 / 5 = 2.4 Newtons.
(b) Final velocity, where v(0) = 0:
(2.4 / 3.30) * 5 = 3.636 m/s.
(c) Final velocity, where v(0) = -2.8:
3.636 - 2.8 = 0.836
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