The magnitude of the net force exerted in the x direction on a 2.35-kg particle

Question

The magnitude of the net force exerted in the x direction on a 2.35-kg particle varies in time as shown in the figure above.

(a) Find the impulse of the force over the 5.00-s time interval. Vector-I _______________ = N ? s ?

(b) Find the final velocity the particle attains if it is originally at rest. Vector-v =______________ m/s ?

(c) Find its final velocity if its original velocity is -2.10 ihatbold m/s. Vector-v =________________ m/s ?

(d) Find the average force exerted on the particle for the time interval between 0 and 5.00 s. Vector-F_______________= N ?

Explanation / Answer

(a) impulse = 12 Newton-seconds. (d) The average force: 12 / 5 = 2.4 Newtons. (b) Final velocity, where v(0) = 0: (2.4 / 3.30) * 5 = 3.636 m/s. (c) Final velocity, where v(0) = -2.8: 3.636 - 2.8 = 0.836

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