A 7.35 H inductor with negligible resistance is placed in series with a 14.1 V b
ID: 2257971 • Letter: A
Question
A 7.35 H inductor with negligible resistance is placed in series with a 14.1 V battery, a 3.00 ? resistor, and a switch. The switch is closed at time t = 0 seconds.
(a) Calculate the initial current at t = 0 seconds.
(b) Calculate the current as time approaches infinity.
(c) Calculate the current at a time of 6.25 s.
(d) Determine how long it takes for the current to reach half of its maximum.
A 7.35 H inductor with negligible resistance is placed in series with a 14.1 V battery, a 3.00 ? resistor, and a switch. The switch is closed at time t = 0 seconds. Calculate the initial current at t = 0 seconds. Calculate the current as time approaches infinity. Calculate the current at a time of 6.25 s. Determine how long it takes for the current to reach half of its maximum.Explanation / Answer
a) at t=0 current I = 0
b) at t=infinty I = 14.1/3 = 4.7 A
c)at t=6.25s
I = 4.7 (1 - e^(-6.25*3/7.35)) = 4.33 A
d) 0.5 = 1 - e^(-t * 3/7.35))
so t = 1.69 s
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