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m8 energy Problem 7.54
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Phys2325 F13 - Signed in as Michael Jackson
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m8 energy Problem 7.54
ResourceseTextConstantsStudy Area
Phys2325 F13 - Signed in as Michael Jackson
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Phys2325 F13 - Signed in as Michael Jackson
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m8 energy Problem 7.54
ResourceseTextConstantsStudy Area
m8 energy Problem 7.54
m8 energy Problem 7.54
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Problem 7.54 You are designing a delivery ramp for crates containing exercise equipment. The crates of weight 1490
N will move with speed 1.9
m/s at the top of a ramp that slopes downward at an angle 23.0
? . The ramp will exert a 582
N force of kinetic friction on each crate, and the maximum force of static friction also has this value. At the bottom of the ramp, each crate will come to rest after compressing a spring a distance
x . Each crate will move a total distance of 7.9
m along the ramp
; this distance includes
x . Once stopped, a crate must not rebound back up the ramp.
Part A Calculate the maximum force constant of the spring
k max that can be used in order to meet the design criteria.
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k max =
N/m of
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m8 energy Problem 7.54
ResourceseTextConstantsStudy Area
You are designing a delivery ramp for crates containing exercise equipment. The crates of weight 1490N will move with speed 1.9m/s at the top of a ramp that slopes downward at an angle 23.0? The ramp will exert a 582N force of kinetic friction on each crate, and the maximum force of static friction also has this value. At the bottom of the ramp, each crate will come to rest after compressing a spring a distance x. Each crate will move total distance of 7.9m along the ramp this distance includes Once stopped, a crate must not rebound back up the ramp Calculate the maximum force constant of the spring k max that can be used in order to meet the design criteria.
Explanation / Answer
the distance x compressed by the block should be such that the force exerted by the spring balances the frictional and gravitational forces.so,
spring force=kx
frictional force=582 N
gravitational force along the incline=1490 sin(23)
=582.189 N
so kx=582+582.189
also we need to conserve energy,
inital energy=final energy+energy lost due to friction
or 0.5*(1490/9.81)*1.9^2 + 3.08*9.81*(1490/9.81) = 0.5*k*x^2+ 582*7.9
so K=2551.9 N/m