Figure shows two unequal point charges Q1 = +4C and Q2 = -2C. The distance betwe

Question

Figure shows two unequal point charges Q1 = +4C and Q2 = -2C. The distance between them is 16 cm.

I) Where, in what region could a net E- field due to this combination be 0. Show calculation.

I believe the answer is region I and III but need to verify that claim with calculations.

Keep calculations as simple as possible, but easy to follow :)

II) find the distance, r, from q = -2 C where the net E-field is 0.

PLEASE PROVIDE EXPLANATION. WILL RATE. THANK YOU!!!

Figure shows two unequal point charges Q1 = +4C and Q2 = -2C. The distance between them is 16 cm. Where, in what region could a net E- field due to this combination be 0. Show calculation. I believe the answer is region I and III but need to verify that claim with calculations. Keep calculations as simple as possible, but easy to follow :) find the distance, r, from q = -2 C where the net E-field is 0.

Explanation / Answer

negative charge has E towards it and positive charge has E away from it....so in region II the E's add up and they wont be 0

region III

let E=0 be at a distance x from -2c charge then

Q1/(R+x)^2 = Q2/x^2

4/(16+x)^2 =2/x^2

2x^2=256+x^2+32x

x^2-32x-256=0

x= 38.627 cm

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