Two stones are launched form the top of a tall building (4.9m tall). one stone i

Question

Two stones are launched form the top of a tall building (4.9m tall). one stone is thrown in a direction 25.0 degrees above the horizontal with a speed of 12.0m/s; the other is thrown in a direction 25.0 degrees below the horizontal with the same speed. which stone spends more time in the air? calculate the time, which stone lands further away form the building? calculate the range. (neglect air resistance)

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Explanation / Answer

first stone

y = y0 + v0y t + 1/2 a t^2

0 = 4.9 + 12*sin(25)*t - 0.5*9.81*t^2

t=1.64 s

x = v0x t = 12*cos(25)*1.64=17.84 m

for second stone

y = y0 + v0y t + 1/2 a t^2

0 = 4.9 - 12*sin(25)*t - 0.5*9.81*t^2

t=0.608 s

x = v0x t = 12*cos(25)*0.608=6.61 m

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