A piano tuner stretches a steel piano wire with a tension of 1040 N . The wire i

Question

  A piano tuner stretches a steel piano wire with a tension of 1040N . The wire is 0.400m  long and has a mass of   3.90g . Part A What is the frequency of its fundamental mode of vibration? f1 =
Hz SubmitMy AnswersGive Up Try Again Part B What is the number of the highest harmonic that could be heard by a person who is capable of hearing frequencies up to 1.00
  A piano tuner stretches a steel piano wire with a tension of 1040N . The wire is 0.400m  long and has a mass of   3.90g .
  A piano tuner stretches a steel piano wire with a tension of 1040N . The wire is 0.400m  long and has a mass of   3.90g .   A piano tuner stretches a steel piano wire with a tension of 1040N . The wire is 0.400m  long and has a mass of   3.90g .   A piano tuner stretches a steel piano wire with a tension of 1040N . The wire is 0.400m  long and has a mass of   3.90g . Part A What is the frequency of its fundamental mode of vibration? f1 =
Hz SubmitMy AnswersGive Up Try Again Part A What is the frequency of its fundamental mode of vibration? f1 =
Hz SubmitMy AnswersGive Up Try Again f1 =
Hz f1 =
Hz SubmitMy AnswersGive Up Try Again Try Again Try Again Part B What is the number of the highest harmonic that could be heard by a person who is capable of hearing frequencies up to 1.00 f1 =
Hz

Explanation / Answer

The mass per unit length is ? = 0.0031kg / 0.4m = 0.00775 kg/m

The fundamental frequency is f = sqrt(T/?) / 2L
f = sqrt(830N/.00775kg/m) / 2*0.4 m = 409 Hz

Highest harmonic heard is 1*10^4Hz / 409Hz = 24th harmonic

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