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Full points will be given to whoever shows their work and has the correct answer in (J/K).

Question below:

"By how much does each square meter of the furnace change the entropy of the factory every second?"

Thank you

A large factory furnace maintained at 180 degree C at its outer surface is wrapped in an insulating blanket of thermal conductivity 5.50 times 10-2W/(m . K) which is thick enough that the outer surface of the insulation is at 45.0 degree C while heat escapes from the furnace at a steady rate of 115W for each square meter of surface area.

Explanation / Answer

Rate of heat transfer = > dQ/dt = KAdT/L

L = KdT/P = 5.5e-2 x (273+(180-45))/115

= 19.51 cm

dQ=TdS

dS = dQ/T

dS/Adt = KdT/LT = 5.5e-2X(408)/(0.195X453)

= 0.254 J/K

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