Figure 1 above for reference only. ***NOTE: PLEASE USE THE FIGURE ABOVE AS A REF

Question

Figure 1 above for reference only.

***NOTE: PLEASE USE THE FIGURE ABOVE AS A REFERENCE ONLY.  PLEASE ONLY USE THE VALUES IN THE WORD PROBLEM BELOW.

Water flows steadily from an open tank into a pipe as shown in the figure, but use the numbers given instead of the numbers in the figure. (Figure 1) The elevation of the top of the tank is

14.9m , and the elevation at the pipe is 2.10m . The initial cross-sectional area of the pipe (at point 2) is 6.90

Water flows steadily from an open tank into a pipe as shown in the figure, but use the numbers given instead of the numbers in the figure. (Figure 1) The elevation of the top of the tank is 14.9m , and the elevation at the pipe is 2.10m . The initial cross-sectional area of the pipe (at point 2) is 6.90times10?2m2 ; and at where the water is discharged from the pipe (at point 3), it is 2.40times10?2m2 . The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe. Assuming that Bernoulli's equation applies, compute the volume of water ?V that flows across the exit of the pipe in the time interval 7.00s .

Explanation / Answer

As we now that

Q = AV = Constant

Therefoe

Here

V at Exit point = sqrt(2gh)

= sqrt(2*9.8*(10-2))

= 12.522 m/sec

Therefore

Q = (2.40*10^-2)*12.522

= 0.3005 m^3/sec

Therefre in 7 sec

Volume = 0.3005*7

= 2.1 m^3

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