A supersonic jet traveling at Mach 2.20 at an altitude of h = 15,000 m is direct

Question

A supersonic jet traveling at Mach 2.20 at an altitude of h = 15,000 m is directly over a person at time t = 0 as shown in the figure below. Assume the average speed of sound in air is 335 m/s over the path of the sound.

A supersonic jet traveling at Mach 2.20 at an altitude of h = 15,000 m is directly over a person at time t = 0 as shown in the figure below. Assume the average speed of sound in air is 335 m/s over the path of the sound. At what time will the person encounter the shock wave due to the sound emitted at t = 0? Where will the plane be when this shock wave is heard? (Give the plane's horizontal displacement x.)

Explanation / Answer

a) t = H/u = 15,000 / 335

= 44.78 s

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b) X = V * t = ( 2.40 * u ) * t

= 2.20 * 335 * 44.78

= 33000 m = 33 km

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