Urgent please! Two conducting metal sphere, each having an excess amount of posi
ID: 2255707 • Letter: U
Question
Urgent please!
Two conducting metal sphere, each having an excess amount of positive charge +Q are separated from one another by a distance r as shown in the picture to the right (assume that no other electrically charged objects are nearby). Where on the spheres does the excess amount of charge lie? How is the electrostatic force acting on the charge on the left compare to the electrostatic force acting on the charge on the right? If the excess positive charge on the left sphere is increased to +6Q, how does the eletrostatic force acting on the sphere on the left compare to the electrostatic force acting on the sphere on the right? How do these forces compare to the electrostatic forces acting on the two spheres before the extra positive charge was added to the left sphere? Supposed that the spheres are connected for a moment with a piece of copper (conducting wire). what will happen? Finally, how do rbe electrostatic forces acting on the original two spheres compare with each other if the distance between the two spheres is tripled? How do these electrostatic forces compare with the electrostatic forces acting between the original two spheres (from the first part of this problem)?Explanation / Answer
The charge lies on the surface of the spheres
Since the magnitude and sign of the charges aew same, the electrostatic force acting on both the spheres will be same.
When the charge is increased, the distance between the two spheres will increaese due to repulsion as the sign of the charges is same and elecromotive force also increaes.
When connected via copper(good conductor), the electrostatic force will change because the dielectric has now changed.
When the distance is 3r, the force is decreaesedby 9 times as the electrostatic force is inversely proportional to the square of the distance.
Hope it was helpful :)
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