An Atwood\'s machine consists of blocks of masses m 1 = 11.0 kg and m 2 = 22.0 k

Question

An Atwood's machine consists of blocks of masses m1 = 11.0 kg and m2 = 22.0 kg attached by a cord running over a pulley as in the figure below. The pulley is a solid cylinder with mass M = 7.00 kg and radius r = 0.200 m. The block of mass m2 is allowed to drop, and the cord turns the pulley without slipping.

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T1 = N T2 = N An Atwood's machine consists of blocks of masses m1 = 11.0 kg and m2 = 22.0 kg attached by a cord running over a pulley as in the figure below. The pulley is a solid cylinder with mass M = 7.00 kg and radius r = 0.200 m. The block of mass m2 is allowed to drop, and the cord turns the pulley without slipping.

Explanation / Answer

a. when the mass M2 moves downward, than due to tension there is rotation in the cylinder, now if the tension is equal than there ll be no rotation and the system ll be at rest...

b. from newtons law we ve

T2 = m2g - m2a

and T1 = m1g+ m1a

also we know dat

torque = Ia

hence T = (T2-T1)R

(0.5)Ma = (m2 - m1)g - (m2 + m1) a

hence accleration ll be

a = (m2 - m1) g / [ (0.5)M + (m1+m2)]

= (22 - 11) (9.8) / [ (0.5)(7) + (11+22)]

= 2.953 m/s^2

c.

tension ll be

T2 = m2g - m2a = (22*9.8 - 22.2.953) = 150.62N

and T1 = m1g+ m1a = 11(9.8+2.953) = 140.283 N

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