The figure below shows a bar of mass m = 0.240 kg that can slide without frictio

Question

The figure below shows a bar of mass m = 0.240 kg that can slide without friction on a pair of rails separated by a distance scripted l = 1.20 m and located on an inclined plane that makes an angle = 34.0° with respect to the ground. The resistance of the resistor is R = 1.50 and a uniform magnetic field of magnitude B = 0.500 T is directed downward, perpendicular to the ground, over the entire region through which the bar moves. With what constant speed v does the bar slide along the rails?

The figure below shows a bar of mass m = 0.240 kg that can slide without friction on a pair of rails separated by a distance scripted l = 1.20 m and located on an inclined plane that makes an angle I¸ = 34.0A degree with respect to the ground. The resistance of the resistor is R = 1.50 I and a uniform magnetic field of magnitude B = 0.500 T is directed downward, perpendicular to the ground, over the entire region through which the bar moves. With what constant speed v does the bar slide along the rails?

Explanation / Answer

Component of B perpendicular to the plane = Bcos34

emf induced in the coil E = Bcos34*1.2*v

current in the bar I = E/R = (v/R) * 1.2 Bcos34

Force opposing the downward motion

F = I * L * Bcos34 = (v/R) * (1.2 Bcos34)^2

As the bar starts sliding, v keeps on increasing and so does F till F balances the downward component of the weight of the bar

mgsin25

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