18) It takes the elevator in a skyscraper 4.2 s to reach its cruising speed of 1

Question

18) It takes the elevator in a skyscraper 4.2s to reach its cruising speed of 12m/s . A 62kg passenger gets aboard on the ground floor.

Part A

What is the passenger's weight before the elevator starts moving?

Express your answer to two significant figures and include the appropriate units.

Part B

What is the passenger's weight while the elevator is speeding up?

Express your answer to two significant figures and include the appropriate units.

Part C

What is the passenger's weight after the elevator reaches its cruising speed?

Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

Acceleration = (v/t) = 12/4.2 = 2.86m/sec^2. up.
1) Weight when speeding up = (ma) = 62 x (g + 2.86) = 785 N.
2) Weight = normal, = (62 x g) = 607.6N.

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