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ID: 2254767 • Letter: H
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Question?Consider the following two-step process. Heat is allowed to flow out of an ideal gas at constant volume so that its pressure drops from
P1 = 2.1atm to P2 = 1.5atm . Then the gas expands at constant pressure, from a volume of V1 = 6.0L to V2 = 9.7L , where the temperature reaches its original value. See the figure.
1.Calculate the total work done by the gas in the process.
2.Calculate the change in internal energy of the gas in the process.
3.Calculate the total heat flow into or out of the gas.
show steps plz?thx~
Consider the following two-step process. Heat is allowed to flow out of an ideal gas at constant volume so that its pressure drops from P1 = 2.1atm to P2 = 1.5atm. Then the gas expands at constant pressure, from a volume of V1 = 6.0L to V2 = 9.7L , where the temperature reaches its original value. See the figure. Calculate the total work done by the gas in the process. Calculate the change in internal energy of the gas in the process. Calculate the total heat flow into or out of the gas.Explanation / Answer
1)
total workdone=(W)a to b +(W)b to c
=0+pdv
=p2(v2-v1)
=1.5*1.01325*10^5(9.7-6)*10^-3
=562.35375 J
2)
dQ=dU+dw
dU=dQ-dw
3)
total heat flow=dQ
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