http://session.masteringphysics.com/problemAsset/1426831/2/p2.17.jpg As shown in
ID: 1481839 • Letter: H
Question
http://session.masteringphysics.com/problemAsset/1426831/2/p2.17.jpg
As shown in the figure, three force vectors act on an object. The magnitudes of the forces as shown in the figure areF1 = 80.0 N, F2 = 60.0 N, and F3 = 40.0 N, where N is the standard SI unit of force. The resultant force acting on the object is given by:
a. 180 N at an angle 60.0 with respect to +x-axis.
The Answer is E: Could you please show the process on how this is done. Thank you!!
b. 60.0 N at an angle 90.0 with respect to +x-axisExplanation / Answer
net x componet of the vector = F1 * cos(30) - F3
net x componet of the vector = 80 * cos(30) - 40
net x componet of the vector = 80 * cos(30) - 40
net x componet of the vector = 29.282 N
net y component of the vector = F2 - F1 * sin(30)
net y component of the vector = 60 - 80 * sin(30)
net y component of the vector = 20 N
resultant force = sqrt(x component^2 + y component^2)
resultant force = sqrt(29.282^2 + 20^2)
resultant force = 35.5 N
angle = 90 - tan-1(y component / x component)
angle = 90 - tan-1(29.282 / 20)
angle = 34.33 degree
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