Manufacturers of wire (and other objects of small dimensions) sometimes use a la

Question

Manufacturers of wire (and other objects of small dimensions) sometimes use a laser to continually monitor the thickness of the product. The wire intercepts the laser beam, producing a diffraction pattern like that of a single slit of the same width as the wire diameter (see Fig. 37-50). Suppose a laser, of wavelength 647.3 nm, illuminates a wire, and the diffraction pattern appears on a screen 2.66 m away. If the desired wire diameter is 1.33 mm, what is the observed distance between the two tenth-order minima (one on each side of the central maximum)?

( )mm

Explanation / Answer

tan? = y/ L... we are looking for 'y' which is the distancefrom the central maximum to any given minima. Single slitdiffraction problem..


slit size is a= 0.00133m
10th minima m=10
?= 647.3x10-9m

sub these values into this equation and find?: a*sin?=m*?

Distance L= 2.66m

From there use tan? = y/L to find y.

Multiply this y value by 2 since it asks for the distance betweenthe two minima which are each located right and left from thecentral maximum.

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