A 350 k g piano slides 3.0 m down a 28 ? incline and is kept from accelerating b

Question

A 350kg piano slides 3.0m down a 28? incline and is kept from accelerating by a man who is pushing back on it parallel to the incline (see the figure(Figure 1) ). Ignore friction.

A) Determine the force exerted by the man.Express your answer to two significant figures and include the appropriate units

B) Determine the work done on the piano by the man.Express your answer to two significant figures and include the appropriate units.

C) Determine the work done on the piano by the force of gravity.Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

force due to gravity = force excerted by the man'

mg*sin28 = F

F = 350*9.8*sin28 = 1610.287 N

b) work done by the man = F*s

since the man is opposing the piano

work done by the man is negative

W = -F*s = -1610.287*3 = -4830.86 J

c) W = mgsin28*s = 1610.287*3 = 4830.86 J

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