17. The interface between regions 1 and 2 is charged with a surface charge densi

Question

17. The interface between regions 1 and 2 is charged with a surface charge density p, 0.2 Cm Region 1 (z > 0) is air, whereas region 2 (0) is a material with e2-2, and 2-3.lpe. If the electric flux density in region 1 is given by D, 3a, + 4Vy a, +3a,, and the magnetic field intensity in region 2 is determine the electric flux density (D,) and the magnetic flux density B, at the interface between regions 1 and 2 in Figure P3.17. Region 1 (air) Ps = 0.2 Cin? Region 2 Figure P3.17 An interface between two media of different dielectric and magnetic properties

Explanation / Answer

E1t=(3i+4*root(y) j) /epsilonot

E1t=E2t

D1n=3 k

D1n-D2n=surface charge density

D2n=2.8 k

D2t=2*epsilonot *E2t

D2=D2t+D2n

H1t-H2t=space current density =0

H1t=H2t=4i+3*square(y) j

H2n=5 k

B1n=B2n=mu2 *H2n=5*mu2 k

B1t=munot *H1t

B1=B1t+B1n

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.