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25 A house has the appliances listed in the following tables along with their da

ID: 2248052 • Letter: 2

Question

25 A house has the appliances listed in the following tables along with their daily energy consumption. Appliance Coffee maker Microwave oven in kWh 10 42 125 78 Hand iron 50 Spotight 1.5 Vacuum cleaner Water heater Hair dryer Televsion 195 Eectric pan 12 2.9 Utility Interconnection Issues and Requirements 111 Appliance Electric piano Mxer Amp fer Rated wattage, W 30 15 30 Daily hours used 8.4 a) Calculate the house's daily energy demand b) If the battery voltage is 12 V, calculate the house's daily amp- hours demand. c) If the available battery has 12 V, a capacity of 300 AH, 80% round-trip efficiency, and 80% depth of discharge, calculate the number of batteries needed for 7 days of storage. d) The available PV module has 120 Wp·the house's location has 5 peak sun hours. Calculate the number of modules needed to satisfy the energy demand of the house.

Explanation / Answer

a) Daily Energy Demand = (10+9+42+125+78+5+50+45+1.5+4+195+2+7+54+2+8+12)/30 + (30*3+15*1+30*3+5*5+8.4*3)/1000

   =649.5/30 + 245.2/1000

= 21.65+0.2452 Kwh

   =21.8952 Kwh

b) houses daily ampere hour demand

   we know that energy e= voltage *current* time

   =V I t

from this ampere hour demand daily (I*t) = e/V

   =daily energy demand / voltage

=21.8952/12

   =1.8246 KAh

c)energy for seven days = daily enery load * 7

   =21.8952 * 7

   =153.2664 Kwh

we have 12 v , 300Ah ,80% discharge and 80% round trip batteries

so energy e = number of batteries * voltage * ampere hour *0.8*0.8

  153.2664 =n * 12* 300*0.8*0.8

153.2664 = n * 2304

   n = 153.2664*103 / 2304

   =66.4642

so approximately 67 batteries are needed to connect in series.

d) We have 120 w PV modules.....sun light is 5 hours effective utilization...

daily energy required = m * rating of each module * time

   21.8952 = m * 120 * 5

   m = 21.8952*103 /600

   =36.492

approximately 37 modules are needed.........

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