Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

2401HW2S1g ,ePhysics question l Cheo: ×(@Convert units. Field StrRX - tudent/Ass

ID: 1871354 • Letter: 2

Question

2401HW2S1g ,ePhysics question l Cheo: ×(@Convert units. Field StrRX - tudent/Assignment-R t?dep= 1 8236362 80 2s0 Need Help? Read It ,Twtetit 12. 0/1 points | Previous Answers SerPSE9 24.P043. My Notes Ask Your Ta o identical conducting spheres each having a radius of 0.500 cm are connected by a light 2.10 m long conducting wire. A charge of 54.0 C 's placed on one of the conductors. Assume the surface distribution of charge on each sphere is uniform. Determine the tension in the wire. 1.24 Your response differs from the correct answer by more than 10%. Double check your calculations, N Need Help? Read I Submit Answer Save Progress Practice Another Version 13. 2 points 1 Previus nswers SarPSE9 24 P047 MFB My Notes Ask Your A solid conducting sphere of radius 2.00 cm has a charge of 8.74 AC. A conducting spherical shell of inner radius 4.00 cm and outer radius 5.00 cm is concentric with the solid sphere and has a charge of-3.40 . Find the electric field at the following radii from the center of this charge configuration. (a) r= 1.00 cm N/C direction The magnitude is zero. ’ (b) r= 3.00 cm magnitude 8730288889N/C direction radially outward (c) r-4.50 cm N/C magnitude o direction The magnitade is zaro d) r= 7.00 cm IR.. I"r 44 AM 2/12/2018 ..114c

Explanation / Answer

12.

The Tension in the wire is determined by force of repulsion between the spheres.

T=FE =KQ1Q2/r2

T=K*(Q/2)*(Q/2)/(L+2R)2

T=(9*109)(54*10-6)2/4*(2.1+2*0.005)2

T=1.47 N

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote