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0.0051 m o l of gas undergoes the process 1 ? 2 ? 3 shown in the figure ( Figure

ID: 2244828 • Letter: 0

Question

0.0051mol of gas undergoes the process 1?2?3shown in the figure(Figure 1) .
Part A What is temperature T1? Express your answer using two significant figures.
Part B What is pressure p2? Express your answer using two significant figures.
Part C What is volume V3?
Part A What is temperature T1? Express your answer using two significant figures.
Part B What is pressure p2? Express your answer using two significant figures.
Part C What is volume V3?
Part A What is temperature T1? Express your answer using two significant figures.
Part B What is pressure p2? Express your answer using two significant figures.
Part C What is volume V3?
Part A What is temperature T1? Express your answer using two significant figures.
Part B What is pressure p2? Express your answer using two significant figures.
Part C What is volume V3?
Part A What is temperature T1? Express your answer using two significant figures.
Part A What is temperature T1? Express your answer using two significant figures.
Part B What is pressure p2? Express your answer using two significant figures.
Part B What is pressure p2? Express your answer using two significant figures.
Part C What is volume V3?
Part C What is volume V3?

























0.0051mol of gas undergoes the process 1?2?3shown in the figure(Figure 1) .
Part A What is temperature T1? Express your answer using two significant figures.
Part B What is pressure p2? Express your answer using two significant figures.
Part C What is volume V3?




















0.0051mol of gas undergoes the process 1?2?3shown in the figure What is temperature T1? Express your answer using two significant figures What is pressure p2? Express your answer using two significant figures. What is volume V3?

Explanation / Answer

Assuming Ideal gas

PV=nRt

At point 1 P=1atm and V=0.1L

=>1*0.1=0.0051*0.082*T=>T=239.1K


At point 2 V=0.3L

=>P*0.3=0.0051*0.082*2926=4.07atm

At point 3 P=2atm

=>2*V=0.0051*0.082*2438=0.509L or 509cm^3

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