0.0050 mol of gas follows the hyperbolic trajectory shown in figure 1. What is t

Question

0.0050 mol of gas follows the hyperbolic trajectory shown in figure 1. What is the initial and final temperature? What is the final volume? 20046 PHY 115 Problem 12 26 Problem 12.26 Part B What is theinitial temperature? 00050 mol of gas follows the hypertoictrajectory shown in Express your answer using two significant figures. Submit My Answers p (atm) Part C What is the final temperature? Express your answer using two significant figures. Submit My Answers V (cm) What is the final volume? O Ask me anything 0 0 a

Explanation / Answer

at point "i"

Pi = initial pressure = 3 atm = 3 x 1.01 x 105 Pa

Vi = initial volume = 100 cm3 = 100 x 10-6 m3

n = number of moles = 0.0050

Ti = temperature at "i"

using the equation

Pi Vi = n R Ti

(3 x 1.01 x 105) (100 x 10-6) = (0.0050) (8.314) Ti

Ti = 728.89 K

b)

since the process is isothermal

hence Tf = Ti = 728.89

c)

Pf = initial pressure = 1 atm = 1 x 1.01 x 105 Pa

Vf = initial volume

using the formula

Pf/Vf = Pi/Vi

(1 x 1.01 x 105)/Vf = (3 x 1.01 x 105) /(100 x 10-6 )

Vf = 0.000033 m3

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