Three carts of masses m 1 = 5.50 kg, m 2 = 9.50 kg, and m 3 = 3.00 kg move on a

Question

Three carts of masses m1 = 5.50 kg, m2 = 9.50 kg, and m3 = 3.00 kg move on a frictionless, horizontal track with speeds of v1 =4.00 m/s to the right, v2 = 3.00 m/s to the right, and v3 = 6.00 m/s to the left, as shown below. Velcro couplers make the carts stick together after colliding.

magnitude m/s direction ---Select---rightleft Three carts of masses m1 = 5.50 kg, m2 = 9.50 kg, and m3 = 3.00 kg move on a frictionless, horizontal track with speeds of v1 =4.00 m/s to the right, v2 = 3.00 m/s to the right, and v3 = 6.00 m/s to the left, as shown below. Velcro couplers make the carts stick together after colliding. Find the final velocity of the train of three carts. Does your answer require that all the carts collide and stick together at the same moment? What if they collide in a different order?

Explanation / Answer

Here

Momentum remains Conserved

Therefore

5.50*4 + 9.50*3 - 3*6 = (5.50+9.50+3)*V

V = 1.80556 m/sec

Towards Right

Yes it is Necessary

Then we consider 2 Equations of Conservation of momentum if they collide at diffrerent times

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