A 2-kg block sits on an incline where the top part of the incline has a coeffici
ID: 2243568 • Letter: A
Question
A 2-kg block sits on an incline where the top part of the incline has a coefficient of kinetic friction (mk) of 0.70. The bottom section of the plane has mk = 0.8. The angle of inclination is 40 degrees. The block is released and travels 10 m along the initial part of the incline and then enters the lower section. Calculate how far the block travels along the second section before it is brought to a stop.
A 2-kg block sits on an incline where the top part of the incline has a coefficient of kinetic friction (mk) of 0.70. The bottom section of the plane has mk = 0.8. The angle of inclination is 40 degrees. The block is released and travels 10 m along the initial part of the incline and then enters the lower section. Calculate how far the block travels along the second section before it is brought to a stop.
A 2-kg block sits on an incline where the top part of the incline has a coefficient of kinetic friction (mk) of 0.70. The bottom section of the plane has mk = 0.8. The angle of inclination is 40 degrees. The block is released and travels 10 m along the initial part of the incline and then enters the lower section. Calculate how far the block travels along the second section before it is brought to a stop.Explanation / Answer
the block will never stop as acceleration on both parts (g*sintheta - mk*costheta) is coming out positive..
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