1) In Fig. 4.1, a 10-kg mass is suspended from two spring scales that read in po

Question

1) In Fig. 4.1, a 10-kg mass is suspended from two spring scales that read in pound, each of which has negligible weight. Thus:

Note is not 10kg is 10lb

A) Each scale will read 5lb.

B) The top scale will read zero, the lower scale will read 10 lb.

C) The lower scale will read zero, the top scale will read 10lb.

D) Each scale will show a reading between one and 10 lb, such that the sum of the two is 10 lb. However, exact readings cannot be determined without more information.

E) None of these is true

Question 2) at breakfast one morning, you notice something printed on your cereal box which says "1.0 lb= 0.454 kg." what is wrong with this information?

Question 3) A satellite weighing 500 kg is in a circular orbit around the earth. It takes exactly 3 hours to go around the earth.

A) how far above the surface  of the earth is the orbit?

B) what is the force of gravity on this satellite?

In Fig. 4.1, a 10-kg mass is suspended from two spring scales that read in pound, each of which has negligible weight. Thus: Note is not 10kg is 10lb Each scale will read 5lb. The top scale will read zero, the lower scale will read 10 lb. The lower scale will read zero, the top scale will read 10lb. Each scale will show a reading between one and 10 lb, such that the sum of the two is 10 lb. However, exact readings cannot be determined without more information. None of these is true at breakfast one morning, you notice something printed on your cereal box which says "1.0 lb= 0.454 kg." what is wrong with this information? A satellite weighing 500 kg is in a circular orbit around the earth. It takes exactly 3 hours to go around the earth. how far above the surface of the earth is the orbit? what is the force of gravity on this satellite?

Explanation / Answer

(1)   E) None of these is true

(2)The pound (lb) is a unit of force, but a kilogram (kg) is a unit of mass. Most likely the manufacturer is making use of the fact that

(0.454 kg)(9.8 m/s2) = 4.45 N

            = 1.0 lb

(3)As seen in the equation v = SQRT(G * Mcentral / R), the mass of the central body (earth) and the radius of the orbit affect orbital speed. The orbital radius is in turn dependent upon the height of the satellite above the earth

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