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Happy (H), Cheddar (D), and Yellow (E). Mutant phenotypes seen for these traits

ID: 224155 • Letter: H

Question

Happy (H), Cheddar (D), and Yellow (E). Mutant phenotypes seen for these traits are expressionless (h), pretzel (d), and brown (e). Data from a three point testcross are shown below.

Phenotype

Number of Progeny

Normal

102

Expressionless

10

Pretzel

804

Brown

94

Expressionless, Pretzel

102

Expressionless, Brown

790

Pretzel, Brown

8

Expressionless, Pretzel, Brown

90

What are the genotypes of the testcross?

x

What is the order of the three genes h, d, and e?

Create a genetic map (including distances) that represents the relationship of the three loci above? (Show all your Work)

Phenotype

Number of Progeny

Normal

102

Expressionless

10

Pretzel

804

Brown

94

Expressionless, Pretzel

102

Expressionless, Brown

790

Pretzel, Brown

8

Expressionless, Pretzel, Brown

90

Explanation / Answer

Answer:

1). Genotype of test cross:

HEd/ heD x hed/hed

2). Orfer of genes is h –-----7.13 m.u.-----e-------7 m.u.------d

Explanation:

Shorthand

Number of progeny

HDE

102

hDE

10

HdE

804

HDe

94

hdE

102

hDe

790

Hde

8

hde

90

Total 3000

Parental combinations are more so, the parental combinations are HdE & hDe

1. If single cross over (SCO) occurs between H & d and h &D

Normal order= H --------d & h ----- D

After cross over= H ----- D & h------d

H ----- D recombinants are 102+94= 196

h------d recombinants are 102+90=194

Total recombinants = 390

RF = (390/3000.)*100 =13%

2. If single cross over (SCO) occurs between d & E and D & e

Normal order= d --------- E & D --------- e

After cross over= d --------- e & D ------ E

d --------- e recombinants are 8+90=98

D ------ E recombinants are 10+102=112

Total recombinants = 210

RF = (210/3000)*100 = 7%

3. If single cross over (SCO) occurs between H & E and h & e

Normal order= H --------- E & h------e

After cross over= H --------- e & h---------E

H --------- e recombinants are 94+8 = 102

h--------- E recombinants are 102+10= 112

Total recombinants = 214

RF = (214/3000)*100 = 7.13%

% RF = Map unit distance

The order of gene is -----

h –-----7.13 m.u.-----e-------7 m.u.------d

Shorthand

Number of progeny

HDE

102

hDE

10

HdE

804

HDe

94

hdE

102

hDe

790

Hde

8

hde

90

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