The left end of a long glass rod 8.00 c m in diameter and with an index of refra

Question

The left end of a long glass rod 8.00cm in diameter and with an index of refraction of 1.60 is ground and polished to a convex hemispherical surface with a radius of 4.00cm . An object in the form of an arrow 1.10mm tall, at right angles to the axis of the rod, is located on the axis 20.0cm to the left of the vertex of the convex surface.

Part A: Find the position of the image of the arrow formed by paraxial rays incident on the convex surface.

Correct answer: 16cm

NEED HELP WITH

Part B:  Find the height of the image formed by paraxial rays incident on the convex surface. Answer needs to be in mm.

Part C:  Is the image erect or inverted?

Explanation / Answer

1/20.0 +1.6/s' = (1.6-1)/4

0.05 + 1.6/s' = 0.15

1.6/s' = 0.1

s' = 16cm

Magntifcation = image height/object height = image distance/object diatance = s'/s

y'/1.1 = 16/20

y' = 0.88mm

image is erect

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