magnitude direction Clockwise A small circular loop of wire of radius 5.0 cm and

Question

magnitude                 direction                                               Clockwise
A small circular loop of wire of radius 5.0 cm and resistance R = 1.6 10-3 ? is centered inside a large circular loop of wire of radius 50 cm (see figure below). The larger loop, which initially carries a current I = 8.9 A, is cut and its current is reduced to zero over a time interval of 9.0 10-7 s. Find the average current in the smaller loop during this time interval. (The magnetic field of the larger loop is approximately constant over the smaller loop.)

Explanation / Answer

induced emf = e = dB*A /dt = (uo*i/2*r2)*(pi*r1^2)*(10^7/9)

e = 2*3.14*10^-7*(1/0.5)*8.9*3.14*0.05^2*10^7*(1/9) = 97.5e?3 Volts

i = e/R = 60.98 A

Related Questions

Navigate

• Browse (All)
• Browse M
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.