A 1300 kg car pushes a 2120 kg truck that has a dead battery. When the driver st

Question

A 1300 kg car pushes a 2120 kg truck that has a dead battery. When the driver steps on the accelerator, the drive wheels of the car push against the ground with a force of 4580 N. Take the friction between the truck's tires and the ground to be 455 N. What is the magnitude of the force the car applies to the truck? What is the magnitude of the force that the car exerts on the truck? Use a coordinate system, where upward is the positive y direction and to the right, the direction points, is the positive x direction.

Explanation / Answer

First calculate the acceleration of the system

using F = m*a

we have a = F/m = (4580 - 455)/(1300 + 2120) =1.2 m/s^2

Now for the free body diagram about the truck we have F_cont - 455 = 2120*1.2

So F_cont = 455 + 2120*1.2 = 2999 N

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