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The switch in the figure is open for a very long time and then closed at t = 0.

ID: 2237925 • Letter: T

Question

The switch in the figure is open for a very long time and then closed at t = 0. ( Use V = 3.7 V, R1 = 867 , R2 = 567 , L = 7.5 mH )

I already know some of them.

What is the current through R1 immediately after the switch is closed?

=3.7/567

What is the current through R2immediately after the switch is closed?

What is the voltage across the inductor immediately after the the switch is closed?

=3.7

After the switch has been closed for a long time what is the current through R1?

After the switch has been closed for a long time what is the current through R2?

After the switch has been closed for a long time what is the voltage across the inductor?

=0

The switch is now opened. What is the current through R11immediately after the switch is opened?


Explanation / Answer

a)when the swithch is closed,

no current will flow through R2 (since the rate of change of flux through the inductor is very high)

so current through R1=V/R

=3/800

b)Ir2=0

c)by KVL,

we get the voltage to be 3 V

d)after a long time, the inductor will allow the current to flow freely,

so the current in R1=V/R1

=3/800

e)current through R2=3/500

f)V inductor=0

e)i=3/500

i have solved it according to the figure given

please comment before rating if incorrect

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